Posts Tagged With: backgammon

I Analyze a Cereal-Box Game

 

Please look at the picture of the Alpha-Bits game. (Sorry, it’s a bit blurry. I have fired my camera man.) You draw from a deck of cards, containing each of the following numbers, 1, 2, 3, and 4. If you draw a 1, you move your piece, an Alpha-Bit letter, ahead one square, and so on. However, there is something funny about the game. Unsettling even.

Starting the game, it is impossible to land anywhere but on the 3rd square, the one with the bee. For . . .

If you draw a 1, then you move to square 1. The result tells you to move ahead two squares to square 3, the one with the bee.

If you draw a 2, then you move to square 2. The result tells you to move ahead one square to square 3, the one with the bee.

If you draw a 3, then you move to square 3, the one with the bee.

If you draw a 4 then you move to square 4. The result tells you to move back square to square 3, the one with the bee.

No matter what you draw, you end up on the bee.

Similarly, if your piece is on square 13, the one with the rocket, no matter what you draw, you’ll finish the game.

Working backwards from square 13, you can determine the expected numbers of turns needed to win the game.

THE EXCITING RESULTS

Square #   Expected Numbers of Turns needed to win the game.

———-   ———————————————————–

13            –         1.00

8              –         2.00

6              –         2.25

5              –         2.56

3*            –         3.15

Start        –         4.15

* = Mathematical excitement abounds if you’re starting on square 3. If you draw a 1, you have to go back to your bee. If in your second turn, you again draw a 1, you will once more be back at the bee square. Fear not! By using the mathematical formula for infinite sums, you can calculate how many turns you can expect to be stuck in this purgatory. (It’s 1.33 turns.) Knowing this, our calculations become simple again.

Note that is impossible to end your turn on squares: 1, 2, 4, 7, 9, 10, 11, 12, 14, 15, 16, 17, 18, and 20.

I have come to believe that the designers of this game never really played it. I am quite certain they never subjected their creation to mathematical analysis.

Please do not use this analysis for betting purposes. And if you do, do not employ a doubling cube as in backgammon.

At any rate, my years of mathematics has served me well. And you get a gold star if you read this blog all the way through.

Paul De Lancey, The Comic Chef, Ph.D., nerd

My cookbook, Following Good Food Around the World, with its 180 wonderful recipes, my newest novel, Do Lutheran Hunks Eat Mushrooms, a hilarious apocalyptic thriller, and all my other books, are available on amazon.com.

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Bacon & Chocolate Party’s Blueprint For Campaign reform

It’s all so simple. Everyone, and I mean everyone, goes to the polling booth on Election Day in
November armed with a die. You can get a die from an old game of Risk or backgammon. Roll the die inside your election booth. If it comes up 1 or 2, vote for President Obama. If the result is 3 0r 4, vote for Romney. However, if you get a 5 or 6 vote for Bacon & Chocolate.

No matter how much money the Democrats or the Republicans spend on the presidential election they cannot affect the roll of the die. They will have no reason to raise an obscene number of millions to spend on misleading and omnipresent campaign ads. Billionaires will have no reason to give money to presidential candidates. Presidential candidates will have no reason to listen to billionaires. No matter, whom we elect when we roll our dice on Election Tuesday, our voice will be heard just as loud to the elected President as any
other.

And we’ll have a 1/3 chance of electing Bacon & Chocolate for  president.

Vote Bacon & Chocolate for a tasty tomorrow.

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